The term independent of x in the binomial expansion of (1 - 1/x + 3x^5)(2x^2 - 1/x)^8 is : - Sarthaks eConnect | Largest Online Education Community
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Find the term independent of x in the expansion of 〖〖(6x^2– 5/x^2 )]8. Binomial Theorem-Maths-Class-11
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How to find the Independent term of "x" in Binomial Expansion|Binomial Theorem(ECAT Part 2 Questions | Binomial theorem, Theorems, The expanse
Without expanding, what is the constant term and middle term for the binomial expansion of (x/2-√2/x^3) ^10? - Quora
If the constant term in the binomial expansion of (√x - (k/x^2))10 is 405, then |k| equals : (1) 2 (2) 1 (3) 3 - Sarthaks eConnect | Largest Online Education Community
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algebra precalculus - Binomial expansion to find a specific term (coefficient) - Mathematics Stack Exchange
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